一个Form
一个TextBox
一个Label

这个修订後的程式是当使用者在TextBox中输入只包含 0~9 的数值後，在Label中就可看见被转换後的中文字，例如：1560890 转成 "壹佰伍拾陆万零捌佰玖拾"。程式限制为不可输入超过16个数字。

请建立一个新专案，并在表单中放入上述物件，再把以下程式码复制到表单的程式
码视窗，最後按下F5来执行。

Private Sub Form_Load()
Text1.MaxLength = 16
Text1.Text = ""
Label1.Caption = ""
Label1.AutoSize = True
Label1.BorderStyle = 1
End Sub

Private Sub Text1_Change()
Label1.Caption = CChinese(Text1.Text)
End Sub

Private Function CChinese(StrEng As String) As String
If Not IsNumeric(StrEng) Or StrEng Like "*.*" Or StrEng Like "*-*" Then
If Trim(StrEng) <> "" Then MsgBox "无效的数字"
CChinese = "": Exit Function
End If
Dim intLen As Integer, intCounter As Integer
Dim strCh As String, strTempCh As String
Dim strSeqCh1 As String, strSeqCh2 As String
Dim strEng2Ch As String
strEng2Ch = "零壹贰叁肆伍陆柒捌玖"
strSeqCh1 = " 拾佰仟 拾佰仟 拾佰仟 拾佰仟"
strSeqCh2 = " 万亿兆"
StrEng = CStr(CDec(StrEng))
intLen = Len(StrEng)
For intCounter = 1 To intLen
strTempCh = Mid(strEng2Ch, Val(Mid(StrEng, intCounter, 1)) + 1, 1)
If strTempCh = "零" And intLen <> 1 Then
If Mid(StrEng, intCounter + 1, 1) = "0" Or (intLen - intCounter + 1) Mod 4 = 1 Then
strTempCh = ""
End If
Else
strTempCh = strTempCh & Trim(Mid(strSeqCh1, intLen - intCounter + 1, 1))
End If
If (intLen - intCounter + 1) Mod 4 = 1 Then
strTempCh = strTempCh & Mid(strSeqCh2, (intLen - intCounter + 1) \ 4 + 1, 1)
If intCounter > 3 Then
If Mid(StrEng, intCounter - 3, 4) = "0000" Then strTempCh = Left(strTempCh, Len(strTempCh) - 1)
End If
End If
strCh = strCh & Trim(strTempCh)
Next
CChinese = strCh
End Function